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3.6.2 The Row Holding the Maximum of a Certain Column

Contents

Task: Find the number, dealer, and price of the most expensive article.

This is easily done with a subquery:

  1. SELECT article, dealer, price
  2. FROM   shop
  3. WHERE  price=(SELECT MAX(price) FROM shop);
  4.  
  5. +---------+--------+-------+
  6. | article | dealer | price |
  7. +---------+--------+-------+
  8. |    0004 | D      | 19.95 |
  9. +---------+--------+-------+

Other solutions are to use a LEFT JOIN or to sort all rows descending by price and get only the first row using the MySQL-specific LIMIT clause:

  1. SELECT s1.article, s1.dealer, s1.price
  2. FROM shop s1
  3. LEFT JOIN shop s2 ON s1.price < s2.price
  4. WHERE s2.article IS NULL;
  5.  
  6. SELECT article, dealer, price
  7. FROM shop
  8. ORDER BY price DESC
  9. LIMIT 1;
Note

If there were several most expensive articles, each with a price of 19.95, the LIMIT solution would show only one of them.


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Document created the 26/06/2006, last modified the 26/10/2018
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References

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